Lesson:
Light-Reflection and Refraction
Question: 1
Which one of the following materials cannot be used to make a
lens?
(a) Water
(b) Glass
(c) Plastic
(d) Clay
Solution
d
Question: 2
The image formed by a concave mirror is observed to be
virtual, erect and larger than the object. Where should be the position of the
object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.
Solution
d
Question: 3
Where should an object be placed in front of a convex lens to
get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal
focus.
Solution
b
Question: 4
A spherical mirror and a thin spherical lens have each a
focal length of -15 cm. The mirror and the lens are likely to be
(a) both concave
(b) both convex
(c) the mirror is concave and the lens is convex
(d) the mirror is convex, but the lens is concave
Solution
a
Question: 5
No matter how far you stand from a mirror, your image appears
erect. The mirror is likely to be
(a) plane
(b) concave
(c) convex
(d) either plane or convex
Solution
d
Question: 6
Which of the following lenses would you prefer to use while
reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm
(b) A concave lens of focal length 50 cm
(c) A convex lens of focal length 5 cm
(d) A concave lens of focal length 5 cm
Solution
c
Question: 7
We wish to obtain an erect image of an object, using a
concave mirror of focal length 15 cm. What should be the range of distance of
the object from the mirror? What is the nature of the image? Is the image
larger or smaller than the object? Draw a ray diagram to show the image
formation in this case.
Solution
Concave mirror forms an erect image of an object when it is
placed between the focus and the pole. Therefore, the range of the distance of
the object = 0 to 15 cm from the pole of the mirror. The image will be virtual,
erect and larger than the object.
Question: 8
Name the type of mirror used in the following situations:
(a) Headlights of a car
(b) Side/rear-view mirror of a vehicle
(c) Solar furnace
Support your answer with reason.
Solution
(a)
Concave Mirror:
When the light source is placed at their
principal focus of a concave mirror, it produces powerful parallel beam of
light. This helps the driver to see considerable distance in the darkness.
(b)
Convex Mirror:
The image formed by the convex mirror is
highly diminished, virtual and erect. This provides a large field of view.
(c)
Concave Mirror:
Concave mirrors can converge the parallel
rays of sun at its principal focus.
The solar furnace when placed at the focus
receives maximum amount of heat.
Question: 9
One-half of a convex lens is covered with a black paper. Will
this lens produce a complete image of the object? Verify your answer
experimentally. Explain your observations.
Solution
Even when one-half of a convex lens is covered with a black
paper, it will form complete
image of an object.
Explanation
(i)
When the
upper half of the lens is covered,
it can be seen that a ray of light coming from the object (AB)
is refracted by the lower half of the lens. These rays meet at the other side
of the lens to form the image of the given object (A’B’).
(ii) When the lower half of the
lens is covered,
it can be seen that a ray of light coming from the object (AB)
is refracted by the lower half of the lens. These rays meet at the other side
of the lens to form the image of the given object (A’B’).
Question: 10
An object 5 cm in length is held 25 cm away from a converging
lens of focal length 10 cm. Draw the ray diagram and find the position, size
and the nature of the image formed.
Solution
Let the height of the object be .
Given that,
Let the distance of the object from converging lens be u.
Given that,
The focal length of converging lens,
Using lens formula,
For a converging lens,
Thus, the image measures 3.3 cm. It is inverted, formed at a
distance of 16.7 cm and is behind the lens. The diagram is shown below.
Question:11
A concave lens of focal length 15 cm forms an image 10 cm
from the lens. How far is the object placed from the lens? Draw the ray
diagram.
Solution
Let
the focal length of concave lens be f.
Given
that
Let the image distance be v.
Given that,
According to the lens formula,
The object is placed 30 cm in front of the lens. The ray
diagram is shown below.
Question: 12
An object is placed at a distance of 10 cm from a convex
mirror of focal length 15 cm. Find the position and nature of the image.
Solution
Let the focal length of the convex mirror be f.
Given that the focal length,
Let the object distance be u.
Give that,
According to the mirror formula,
The
image is formed behind the mirror.
Magnification,
Thus, the image formed is virtual and erect.
Question:13
The magnification produced by a plane mirror is +1. What does
this mean?
Solution
The positive sign means image formed is virtual and erect. The
magnification by 1 means the image size is same as the object size.
Question: 14
An object 5 cm is placed at a distance of 20 cm in front of a
convex mirror of radius of curvature 30 cm. Find the position, nature and size
of the image.
Solution
Given,
The object distance, ,
Object height, ,
Radius of curvature,
According to the mirror formula,
The image is formed behind the mirror.
Magnification,
m = image distance/object distance
The image formed is virtual.
Magnification
(m) = height of the image/height of
the object
The image formed is erect.
The image formed is virtual, erect, and smaller in size.
Question:15
An object of size 7.0 cm is placed at 27 cm in front of a
concave mirror of focal length 18 cm. At what distance from the mirror should a
screen be placed, so that a sharp focused image can be obtained? Find the size
and the nature of the image.
Solution
Given:
Object distance, ,
Object height, ,
Focal length,
According to the mirror formula,
The
screen should be placed at a distance of 54 cm in front of the given mirror.
Magnification,
m = image distance/object distance
The image is real.
Magnification,
height of the image/height of the object
The image formed is inverted.
Question:16
Find the focal length of a lens of power -2.0 D. What type of
lens is this?
Solution
Power of lens,
Given,
Thus, it is a concave lens.
Question:17
A doctor has prescribed a corrective lens of power +1.5 D.
Find the focal length of the lens. Is the prescribed lens diverging or
converging?
Solution
Power of lens, .
Given, P = 1.5 D
It is a convex lens or a converging lens.