Lesson: Motion and Time

Very Short Answer Questions (7 Q.)

Question: 1

Define motion.

Solution:

The change in position of a body with respect to time is called motion.

Question: 2

Write S.I. unit of speed and time.

Solution:

S.I. unit of speed is metre per second (m/s) and S.I. unit of time is second (s).

Question: 3

What is a speedometer?

Solution:

It is a device that is used to measure the speed of the vehicle in km/h.

Question: 4

Define time period of a simple pendulum.

Solution:

The time taken by a simple pendulum to complete one oscillation is called its time period.

Question: 5

Name any two ancient clocks that are used to measure time?

Solution:

Sand clock and water clock

Short Answer Questions (7 Q.)

Question: 1

Define distance and speed.

Solution:

Distance: The distance covered by a moving object is the actual length of the path followed by the object.

Speed: Speed is the total distance covered divided by the total time taken.

Question: 2

Define periodic motion and give an example.

Solution:

When an object repeats its motion after an equal interval of time, this type of motion is called periodic motion.

Example: Motion of a simple pendulum

Question: 3

What is odometer? What is its function?

Solution:

It is a device that records total distance covered by the vehicle. It is used in vehicles to calculate the distance travelled in a particular journey.

Question: 4

Define oscillation? On which factor does the time period of a pendulum depend?

Solution:

The pendulum completes one oscillation when its bob moves from one extreme position A to the other extreme position B and comes back to A.

The time period of a simple pendulum depends on the length of the pendulum.

Question: 5

Express 72 km/h in m/s.

Solution:

72 km/h =  72 ×1000 60×60 = MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaadaWcaa qaaiaabccacaqG3aGaaeOmaiaabccacqGHxdaTcaaIXaGaaGimaiaa icdacaaIWaaabaGaaGOnaiaaicdacqGHxdaTcaaI2aGaaGimaaaacq GH9aqpaaa@4581@  20 m/s

Question: 6

The distance between two stations is 120 km. A train takes 2 hours to cover this distance. Calculate the speed of the train.

Solution:

Distance travelled= 120 km

Time taken = 2 h

Speed = distance travelled time taken MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaadaWcaa qaaiaabsgacaqGPbGaae4CaiaabshacaqGHbGaaeOBaiaabogacaqG LbGaaeiiaiaabshacaqGYbGaaeyyaiaabAhacaqGLbGaaeiBaiaabY gacaqGLbGaaeizaaqaaiaabshacaqGPbGaaeyBaiaabwgacaqGGaGa aeiDaiaabggacaqGRbGaaeyzaiaab6gaaaaaaa@5120@   

= 120 2 = MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacqGH9a qpdaWcaaqaaiaaigdacaaIYaGaaGimaaqaaiaaikdaaaGaeyypa0da aa@3CB5@  60 km/h

Long Answer Questions (6 Q.)

Question: 1

What are the different types of motion?

Solution:

Rectilinear motion: Motion of an object along a straight line is called a rectilinear motion. Example MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaieaaju gGbabaaaaaaaaapeGaa83eGaaa@3978@  A parade

Circular motion: Motion of an object along a circular path is called a circular motion. Example MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaieaaju gGbabaaaaaaaaapeGaa83eGaaa@3978@  A spinning top

Oscillatory motion: The to and fro motion of an object is called an oscillatory motion. Example MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaieaaju gGbabaaaaaaaaapeGaa83eGaaa@3978@  A simple pendulum

Periodic motion: The motion of an object that is repeated at regular interval is called a periodic motion. Example MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaieaaju gGbabaaaaaaaaapeGaa83eGaaa@3978@  Revolution of Earth around the Sun

Question: 2

The odometer of a car reads 5500.0 km when the clock shows the time 06:30 p.m. What is the distance moved by the car, if at 06:50 p.m., the odometer reading has changed to 5530.0 km? Calculate the speed of the car in km/h for this duration.

Solution:

Distance travelled by the car between 06:30 p.m. and 06:50 p.m.

 = 5530.0 km − 5500.0 km

= 30 km

Time taken by the car to cover that distance

= 06:50 p.m. − 06:30 p.m.  

= 20 m

= 20/60 h

= 1/3 /h

Speed of the car in km/min

= 30 20 =1.5 km/min MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacqGH9a qpdaWcaaqaaiaaiodacaaIWaaabaGaaGOmaiaaicdaaaGaeyypa0Ja aGymaiaac6cacaaI1aGaaeiiaiaabUgacaqGTbGaai4laiaab2gaca qGPbGaaeOBaaaa@44E2@

Speed of the car in km/h

=30 km÷ 1 3 =30× 3 1 =90km/h MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaaaa aaaaWdbiabg2da9iaaiodacaaIWaGaaeiiaiaakUgacaGITbGaey49 aG7aaSaaaeaacaaIXaaabaGaaG4maaaacqGH9aqpcaaIZaGaaGimai abgEna0oaalaaabaGaaG4maaqaaiaaigdaaaGaeyypa0JaaGyoaiaa icdacaaMc8Uaae4Aaiaab2gacaqGVaGaaeiAaaaa@4E43@

Question: 3

A simple pendulum takes 20 seconds to complete 5 oscillations. Calculate the time taken by the pendulum to complete 20 oscillations.

Solution:

The time taken by a pendulum to complete 5 oscillations = 20sec

The time taken by the pendulum to complete 1 oscillation = 25 5 = MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaaaa aaaaWdbiabg2da9maalaaabaGaaGOmaiaaiwdaaeaacaaI1aaaaiab g2da9aaa@3C21@  4 sec

Therefore, the time taken by the pendulum to complete 20 oscillations =20×4=80sec MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaaqaaaaa aaaaWdbiabg2da9iaaikdacaaIWaGaey41aqRaaGinaiabg2da9iaa ykW7caaI4aGaaGimaiaaykW7ciGGZbGaaiyzaiaacogaaaa@457D@

Question: 4

The given figure represents distance-time graph. Answer the following questions.

(a)               What is the distance covered after 8 sec?

(b)               Calculate the speed of the object between 12 s and 20 s.

 

Solution:

(a)               The distance covered by the object after 8 second is 4 m.

(b)               Distance travelled between 12th sec and 20th sec

=86=2 m MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacqGH9a qpcaaI4aGaeyOeI0IaaGOnaiabg2da9iaaikdacaqGGaGaaeyBaaaa @3E76@ .

Time interval 2012=8 sec MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacaaIYa GaaGimaiabgkHiTiaaigdacaaIYaGaeyypa0JaaGioaiaabccacaqG ZbGaaeyzaiaabogaaaa@40B5@

Speed = Distance travelled time taken MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaadaWcaa qaaiaabseacaqGPbGaae4CaiaabshacaqGHbGaaeOBaiaabogacaqG LbGaaeiiaiaabshacaqGYbGaaeyyaiaabAhacaqGLbGaaeiBaiaabY gacaqGLbGaaeizaaqaaiaabshacaqGPbGaaeyBaiaabwgacaqGGaGa aeiDaiaabggacaqGRbGaaeyzaiaab6gaaaaaaa@5100@   = 2 8 = MathType@MTEF@5@5@+= feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqr1ngB PrgifHhDYfgasaacH8srps0lbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0x c9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8fr Fve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaeaaeaaakeaacqGH9a qpdaWcaaqaaiaaikdaaeaacaaI4aaaaiabg2da9aaa@3B46@  0.25 m/s